The Black-Scholes formula I

The original derivation of the Black-Scholes [BS] formula is based on a replicating portfolio that ensures that no arbitrage opportunities are allowed. As in the discrete case we consider a portfolio $ \mathbf{H}=\left\{ H\left( t\right) \right\}
_{t\geq 0}$ which is $ \mathscr{F}\left( t\right) $-measurable [we can choose as we go, but at any point in time the choice is deterministic]. $ H\left( t\right) $ denotes the number of shares that we are holding at time $ t$, the rest of our money will be invested in the money market account, giving us a risk free rate of return, $ r$.

The stock, $ S\left( t\right) $, follows a geometric Brownian motion

$\displaystyle \frac{dS\left( t\right) }{S\left( t\right) }=\mu dt+\sigma dB\left( t\right)$   .

Then the wealth of the investor, $ X\left( t\right) $, will follow a diffusion given by [with time suppressed]
$\displaystyle dX$ $\displaystyle =$ $\displaystyle HdS+r\left( X-HS\right) dt$  
  $\displaystyle =$ $\displaystyle \left[ rX+HS\left( \mu -r\right) \right] dt+HS\sigma dB$,  

where one can observe the presence of the risk premium $ \mu -r$.

Now we can value a European claim which will have payoffs $ g\left[ S\left(
T\right) \right] $ at time $ T$. Suppose that the value of this claim at time $ t$ is given by $ G\left( t\right) =f\left( S,t\right) $ when $ S=S\left(
t\right) $. Applying Itô's formula to this function yields

$\displaystyle dG=\left[ f_{t}+\mu Sf_{S}+\frac{1}{2}\sigma ^{2}S^{2}f_{SS}\right]
dt+\sigma Sf_{S}dB$.

Now a replicating portfolio $ \mathbf{H}
$ would track the value of $ %%
G\left( t\right) $ for all $ t\in \left[ 0,T\right] $. We saw above that the value of such a portfolio [the wealth of the investor] will be equal to

$\displaystyle dX=\left[ rX+HS\left( \mu -r\right) \right] dt+HS\sigma dB$.

Observe that both diffusions are [as expected of course] driven by the same Brownian motion. In order for the portfolio to track $ G\left( t\right) $ at all times [mathematically $ X\left( t\right) =G\left( t\right) =f\left(
S,t\right) $ for all $ t\in \left[ 0,T\right] $] one can just equate the coefficients. The fact that this is feasible implies that the market under these assumptions is complete, since a claim with a generic payoff function $ g\left[ S\left( t\right) \right] $ can be replicated. The resulting relations are

$\displaystyle f_{t}+\mu Sf_{S}+\frac{1}{2}\sigma ^{2}S^{2}f_{SS}$ $\displaystyle =$ $\displaystyle rX+HS\left( \mu
-r\right)$   , and  
$\displaystyle \sigma Sf_{S}$ $\displaystyle =$ $\displaystyle HS\sigma$   .  

The second equation will give the delta-hedging rule

$\displaystyle H\left( t\right) =f_{S}\left( S,t\right)$   ;

while the first equation, using the fact that $ X\left( t\right) =f\left(
S,t\right) $ yields that

$\displaystyle f_{t}\left( S,t\right) +rSf_{S}\left( S,t\right) +\frac{1}{2}\sigma
^{2}S^{2}f_{SS}\left( S,t\right) =rf\left( S,t\right)$   .

This is the BS partial differential equation [PDE]. The terminal condition that has to be satisfied is that

$\displaystyle f\left( S,T\right) =g\left( S\right)$   .

Apparently the BS PDE can be used for all European contracts, depending on the payoff function $ g\left( S\right) $. For example

$\displaystyle \begin{tabular}{ll}
European Calls & $g\left( S\right) =\left( S-...
...\left( S\right) =V\mathfrak{I}\left[ S\geq K\right] $ \\
etc. &
\end{tabular}$

BS give the solution of the PDE above for the European call $ C_{BS}=f\left(
S,0\right) $ when $ S=S\left( 0\right) $

$\displaystyle C_{BS}\left( S,K,T,r,\sigma \right) =S\Phi\left( d_{1}\right)
-Ke^{-rT}\Phi\left( d_{2}\right)
$

where $ \mathcal{N}\left( \cdot \right) $ is the cumulative normal distribution function,
$\displaystyle d_{1}$ $\displaystyle =$ $\displaystyle \frac{\ln \left( \frac{S}{K}\right) +\left( r+\frac{\sigma ^{2}}{2}%%
\right) T}{\sigma \sqrt{T}}\text{, and}$  
$\displaystyle d_{2}$ $\displaystyle =$ $\displaystyle d_{1}-\sigma \sqrt{T}$.  

Kyriakos 2003-03-17